Finding the index of an item given a list containing it in Pythonpython
One thing that is really helpful in learning Python is to use the interactive help function:
>>> help(["foo", "bar", "baz"]) Help on list object: class list(object) ... | | index(...) | L.index(value, [start, [stop]]) -> integer -- return first index of value |
which will often lead you to the method you are looking for.
For a list
["foo", "bar", "baz"] and an item in the list
"bar", what's the cleanest way to get its index (1) in Python?
Python: finding an element in an array
The best way is probably to use the list method .index.
For the objects in the list, you can do something like:
def __eq__(self, other): return self.Value == other.Value
with any special processing you need.
You can also use a for/in statement with enumerate(arr)
Example of finding the index of an item that has value > 100.
for index, item in enumerate(arr): if item > 100: return index, item
If you just want to find out if an element is contained in the list or not:
>>> li ['a', 'b', 'new', 'mpilgrim', 'z', 'example', 'new', 'two', 'elements'] >>> 'example' in li True >>> 'damn' in li False
I think you can do it by this
TupList = [('ABC D','235'),('EFG H','462')] if ('ABC D','235') in TupList: print TupList.index(i)