[Javascript] How to check a radio button with jQuery?


Answers

Try this.

In this example, I'm targeting it with its input name and value

$("input[name=background][value='some value']").prop("checked",true);

Good to know: in case of multi-word value, it will work because of apostrophes, too.

Question

I try to check a radio button with jQuery. Here's my code:

<form>
    <div id='type'>
        <input type='radio' id='radio_1' name='type' value='1' />
        <input type='radio' id='radio_2' name='type' value='2' />
        <input type='radio' id='radio_3' name='type' value='3' /> 
    </div>
</form>

And the JavaScript:

jQuery("#radio_1").attr('checked', true);

Doesn't work:

jQuery("input[value='1']").attr('checked', true);

Doesn't work:

jQuery('input:radio[name="type"]').filter('[value="1"]').attr('checked', true);

Doesn't work:

Do you have another idea? What am I missing?




Yes, it worked for me like a way:

$("#radio_1").attr('checked', 'checked');



Just in case anyone is trying to achieve this while using jQuery UI, you will also need to refresh the UI checkbox object to reflect the updated value:

$("#option2").prop("checked", true); // Check id option2
$("input[name='radio_options']").button("refresh"); // Refresh button set



I use this code:

I'm sorry for English.

var $j = jQuery.noConflict();

$j(function() {
    // add handler
    $j('#radio-1, #radio-2').click(function(){

        // find all checked and cancel checked
        $j('input:radio:checked').prop('checked', false);

        // this radio add cheked
        $j(this).prop('checked', true);
    });
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<fieldset class="section">
  <legend>Radio buttons</legend>
  <label>
    <input type="radio" id="radio-1" checked>
    Option one is this and that&mdash;be sure to include why it's great
  </label>
  <br>
  <label>
    <input type="radio" id="radio-2">
    Option two can be something else
  </label>
</fieldset>



The $.prop way is better:

$(document).ready(function () {                            
    $("#radio_1").prop('checked', true);        
});

and you can test it like the following:

$(document).ready(function () {                            
    $("#radio_1, #radio_2", "#radio_3").change(function () {
        if ($("#radio_1").is(":checked")) {
            $('#div1').show();
        }
        else if ($("#radio_2").is(":checked")) {
            $('#div2').show();
        }
        else 
            $('#div3').show();
    });        
});



Short and easy to read option:

$("#radio_1").is(":checked")

It returns true or false, so you can use it in "if" statement.







Try this

var isChecked = $("#radio_1")[0].checked;



$("#radio_1").attr('checked', true);
//or
$("#radio_1").attr('checked', 'checked');



We should want to tell it is a radio button.So please try with following code.

$("input[type='radio'][name='userRadionButtonName']").prop('checked', true);



try this

 $("input:checked", "#radioButton").val()

if checked returns True if not checked returns False

jQuery v1.10.1



I've just have a similar problem, a simple solution is to just use:

.click()

Any other solution will work if you refresh radio after calling function.