[gcc] I don't understand -Wl,-rpath -Wl,


Answers

You could also write

-Wl,-rpath=.

To get rid of that pesky space. It's arguably more readable than adding extra commas (it's exactly what gets passed to ld).

Question

For convenience I added the relevant manpages below.

My (mis)understanding first: If I need to separate options with ,, that means that the second -Wl is not another option because it comes before , which means it is an argument to the -rpath option.

I don't understand how -rpath can have a -Wl,. argument!

What would make sense in my mind would be this:

-Wl,-rpath .

This should invoke -rpath linker option with the current directory argument.


man gcc:

-Wl,option

Pass option as an option to the linker. If option contains commas, it is split into multiple options at the commas. You can use this syntax to pass an argument to the option. For example, -Wl,-Map,output.map passes -Map output.map to the linker. When using the GNU linker, you can also get the same effect with `-Wl,-Map=output.map'.

man ld:

-rpath=dir

Add a directory to the runtime library search path. This is used when linking an ELF executable with shared objects. All -rpath arguments are concatenated and passed to the runtime linker, which uses them to locate shared objects at runtime. The -rpath option is also used when locating shared objects which are needed by shared objects explicitly included in the link;




The man page makes it pretty clear. If you want to pass two arguments (-rpath and .) to the linker you can write

-Wl,-rpath,.

or alternatively

-Wl,-rpath -Wl,.

The arguments -Wl,-rpath . you suggested do NOT make sense to my mind. How is gcc supposed to know that your second argument (.) is supposed to be passed to the linker instead of being interpreted normally? The only way it would be able to know that is if it had insider knowledge of all possible linker arguments so it knew that -rpath required an argument after it.




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gcc   ld   rpath