python How to emulate sum() using a list comprehension?
>>> from operator import mul >>> nums = [1, 2, 3] >>> reduce(mul, nums) 6
On Python 3 you will need to add this import:
from functools import reduce
2.6 You could use
vars()['_'] to refer to the list comprehension currently under construction. This is horrible and should never be used but it's the closest thing to what you mentioned in the question (using a list comp to emulate a product).
>>> nums = [1, 2, 3] >>> [n * (vars()['_'] or )[-1] for n in nums][-1] 6
Is it possible to emulate something like sum() using list comprehension ?
For example - I need to calculate the product of all elements in a list :
list = [1, 2, 3] product = [magic_here for i in list] #product is expected to be 6
Code that is doing the same :
def product_of(input): result = 1 for i in input: result *= i return result
Something like this:
>>> a = [1,2,3] >>> reduce(lambda x, y: x*y, a) 6
I complement the answer of Ignacio Vazquez-Abrams with some code that uses the
reduce operator of Python.
list_of_numbers = [1, 5, 10, 100] reduce(lambda x, y: x + y, list_of_numbers)
which can also be written as
list_of_numbers = [1, 5, 10, 100] def sum(x, y): return x + y reduce(sum, list_of_numbers)
Bonus: Python provides this functionality in the built-in
sum function. This is the most readable expression imo.
list_of_numbers = [1, 5, 10, 100] sum(list_of_numbers)
It is possible to achieve by using lambda with list comprehension Since we can't assign a value in list comprehension we go with lambda
>>> (lambda number_list, sum=0:[sum for number in number_list for sum in [sum + number]][-1])([1, 2, 3, 4, 5]) >>> 15