python example - What is the difference between os.path.basename()and os.path.dirname()?




without extension (2)

Both functions use the os.path.split(path) function to split the pathname path into a pair; (head, tail).

The os.path.dirname(path) function returns the head of the path.

E.g.: The dirname of '/foo/bar/item' is '/foo/bar'.

The os.path.basename(path) function returns the tail of the path.

E.g.: The basename of '/foo/bar/item' returns 'item'

From: http://docs.python.org/2/library/os.path.html#os.path.basename

I'm new in Python programming and while studying I had this doubt about this two functions. I already searched for answers and read some links, but didn't understood. Can anyone give some simple explanation?


I reproduced the original result on my computer using g++ on a Mac.

Adding the following statements to the C++ version just before the while loop brings it inline with the Python version:

std::ios_base::sync_with_stdio(false);
char buffer[1048576];
std::cin.rdbuf()->pubsetbuf(buffer, sizeof(buffer));

sync_with_stdio improved speed to 2 seconds, and setting a larger buffer brought it down to 1 second.





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