compare - type - what does comparable mean in swift




How do I implement Swift's Comparable protocol? (2)

The Comparable protocol extends the Equatable protocol -> implement both of them

In Apple's Reference is an example from Apple (within the Comparable protocol reference) you can see how you should do it: Don't put the operation implementations within the class, but rather on the outside/global scope. Also you only have to implement the < operator from Comparable protocol and == from Equatable protocol.

Correct example:

class Person : Comparable {
    let name : String

    init(name : String) {
        self.name = name
    }
}

func < (lhs: Person, rhs: Person) -> Bool {
    return lhs.name < rhs.name
}

func == (lhs: Person, rhs: Person) -> Bool {
    return lhs.name == rhs.name
}

let paul = Person(name: "Paul")
let otherPaul = Person(name: "Paul")
let ben = Person(name: "Ben")

paul > otherPaul  // false
paul <= ben       // false
paul == otherPaul // true

How do I use the Comparable protocol in Swift? In the declaration it says I'd have to implement the three operations <, <= and >=. I put all those in the class but it doesn't work. Also do I need to have all three of them? Because it should be possible to deduce all of them from a single one.


Update for Swift 3 for Kametrixom answer

class Person : Comparable {
let name : String

init(name : String) {
    self.name = name
}


static func < (lhs: Person, rhs: Person) -> Bool {
    return lhs.name < rhs.name
}

static func == (lhs: Person, rhs: Person) -> Bool {
    return lhs.name == rhs.name
}

}

// then call from some other place

let paul = Person(name: "Paul")
let otherPaul = Person(name: "Paul")
let ben = Person(name: "Ben")

print(paul > otherPaul)  // false
print(paul <= ben)       // false
print(paul == otherPaul) // true