variable - swift unwrap optional string

How to print a string from plist without “Optional”? (4)

Swift 3.1

From Swift 3, you can use String(describing:) to print out optional value. But the syntax is quite suck and the result isn't easy to see in console log.

So that I create a extension of Optional to make a consistent nil value.

extension Optional {
    var logable: Any {
        switch self {
        case .none:
            return "⁉️" // Change you whatever you want
        case let .some(value):
            return value

How to use:

var a, b: Int?
a = nil
b = 1000
print("a: ", a.logable)
print("b: ", b.logable)


a: ⁉️
b: 1000

I load a value from a dictionary in a plist but when I print it to the console, it prints: Optional(Monday Title) rather than just "Monday Title".

How can I get rid of the Optional() of my value when printing?

var plistPath = NSBundle.mainBundle().pathForResource("days", ofType: "plist")
var plistArray = NSArray(contentsOfFile: plistPath!) as NSArray!

    for obj: AnyObject in plistArray {
        if var dicInfo = obj as? NSDictionary {
            let todayTitle: AnyObject? = dicInfo.valueForKey("Title")

Another, slightly more compact, way (clearly debatable, but it's at least a single liner)

(result["ip"] ?? "unavailable").description.

In theory result["ip"] ?? "unavailable" should have work too, but it doesn't, unless in 2.2

Of course, replace "unavailable" with whatever suits you: "nil", "not found" etc

One way to get rid of the Optional is to use an exclamation point:


However, you should do it only if you are certain that the value is there. Another way is to unwrap and use a conditional, like this:

if let theTitle = todayTitle {

Paste this program into runswiftlang for a demo:

let todayTitle : String? = "today"
if let theTitle = todayTitle {

With some try, I think this way is better.

(variableName ?? "default value")!

Use ?? for default value and then use ! for unwrap optional variable.

Here is example,

var a:String? = nil
var b:String? = "Hello"

print("varA = \( (a ?? "variable A is nil.")! )")
print("varB = \( (b ?? "variable B is nil.")! )")

It will print

varA = variable A is nil.
varB = Hello