c++ - work - what does argv and argc indicate in command line arguments

Is “argv[0]=name-of-executable” an accepted standard or just a common convention? (5)

This page states:

The element argv[0] normally contains the name of the program, but this shouldn't be relied upon - anyway it is unusual for a program not to know its own name!

However, other pages seem to back up the fact that it is always the name of the executable. This one states:

You’ll notice that argv[0] is the path and name of the program itself. This allows the program to discover information about itself. It also adds one more to the array of program arguments, so a common error when fetching command-line arguments is to grab argv[0] when you want argv[1].

When passing argument to main() in a C or C++ application, will argv[0] always be the name of the executable? Or is this just a common convention and not guaranteed to be true 100% of the time?

Runnable POSIX execve example where argv[0] != executable name

Others mentioned exec, but here is a runnable example.


#define _XOPEN_SOURCE 700
#include <unistd.h>

int main(void) {
    char *argv[] = {"yada yada", NULL};
    char *envp[] = {NULL};
    execve("b.out", argv, envp);


#include <stdio.h>

int main(int argc, char **argv) {


gcc a.c -o a.out
gcc b.c -o b.out


yada yada

Yes, argv[0] could also be:

Tested on Ubuntu 16.10.

Guesswork (even educated guesswork) is fun but you really need to go to the standards documents to be sure. For example, ISO C11 states (my emphasis):

If the value of argc is greater than zero, the string pointed to by argv[0] represents the program name; argv[0][0] shall be the null character if the program name is not available from the host environment.

So no, it's only the program name if that name is available. And it "represents" the program name, not necessarily is the program name. The section before that states:

If the value of argc is greater than zero, the array members argv[0] through argv[argc-1] inclusive shall contain pointers to strings, which are given implementation-defined values by the host environment prior to program startup.

This is unchanged from C99, the previous standard, and means that even the values are not dictated by the standard - it's up to the implementation entirely.

This means that the program name can be empty if the host environment doesn't provide it, and anything else if the host environment does provide it, provided that "anything else" somehow represents the program name. In my more sadistic moments, I would consider translating it into Swahili, running it through a substitution cipher then storing it in reverse byte order :-).

However, implementation-defined does have a specific meaning in the ISO standards - the implementation must document how it works. So even UNIX, which can put anything it likes into argv[0] with the exec family of calls, has to (and does) document it.

I'm not sure whether it is a nearly universal convention or a standard, but either way you should abide by it. I've never seen it exploited outside of Unix and Unix-like systems, though. In Unix environments - and maybe particularly in the old days - programs might have significantly different behaviors depending on the name under which they are invoked.

EDITED: I see from other posts at the same time as mine that someone has identified it as coming from a particular standard, but I'm sure the convention long predates the standard.

Under *nix type systems with exec*() calls, argv[0] will be whatever the caller puts into the argv0 spot in the exec*() call.

The shell uses the convention that this is the program name, and most other programs follow the same convention, so argv[0] usually the program name.

But a rogue Unix program can call exec() and make argv[0] anything it likes, so no matter what the C standard says, you can't count on this 100% of the time.