v-model - Vuejs get old value when on change event




onchange textbox (7)

Please refer to my snippet below. How can I get the old value of the changed model, in this case is the age in vuejs?

var app = new Vue({
  el:"#table1",
  data:{
   items:[{name:'long name One',age:21},{name:'long name Two',age:22}]
  },
  methods:{
    changeAge:function(item,event){
      alert(item.age);
    }
  }
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="https://unpkg.com/vue/dist/vue.js"></script>

<table class="table table-cart" id="table1">
   <thead>
     <tr>
       <th>Name</th>
       <th>Age</th>
     </tr>
  </thead>
   <tbody>
     <tr v-for="(item,index) in items">
       <td>{{item.name}} :</td>       
       <td>
         <input type="text" name="qty"
                v-model="item.age"   
                @change="changeAge(item,$event)">
       </td>
     </tr>
   </tbody>
 </table>

I am trying to use watch, but I am not able to find any help in watching the age an array of items.


Answers

You dont get old value of element on-change as explained here. Also when watching an object, you can not get older value as explained here until the reference of object changes.

To work around these you can create a computed property which will be clone of your items data, and you can put a watcher over this computed property to get to know the old value as well, See working code below:

var app = new Vue({
  el:"#table1",
  data:{
   items:[{name:'long name One',age:21},{name:'long name Two',age:22}]
  },
  watch:{
    clonedItems: function(newVal, oldVal){
      alert(JSON.stringify(newVal));
      alert(JSON.stringify(oldVal));
    }
  },
  computed:{
    clonedItems: function(){
       return JSON.parse(JSON.stringify(this.items))
    }
  }
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="https://unpkg.com/vue/dist/vue.js"></script>

<table class="table table-cart" id="table1">
   <thead>
     <tr>
       <th>Name</th>
       <th>Age</th>
     </tr>
  </thead>
   <tbody>
     <tr v-for="(item,index) in items">
       <td>{{item.name}} :</td>       
       <td>
         <input type="text" name="qty"
                v-model="item.age">
       </td>
     </tr>
   </tbody>
 </table>


What is the most efficient way to deep clone an object in JavaScript?

Note: This is a reply to another answer, not a proper response to this question. If you wish to have fast object cloning please follow Corban's advice in their answer to this question.


I want to note that the .clone() method in jQuery only clones DOM elements. In order to clone JavaScript objects, you would do:

// Shallow copy
var newObject = jQuery.extend({}, oldObject);

// Deep copy
var newObject = jQuery.extend(true, {}, oldObject);

More information can be found in the jQuery documentation.

I also want to note that the deep copy is actually much smarter than what is shown above – it's able to avoid many traps (trying to deep extend a DOM element, for example). It's used frequently in jQuery core and in plugins to great effect.


Assuming that you have only variables and not any functions in your object, you can just use:

var newObject = JSON.parse(JSON.stringify(oldObject));

Checkout this benchmark: http://jsben.ch/#/bWfk9

In my previous tests where speed was a main concern I found

JSON.parse(JSON.stringify(obj))

to be the fastest way to deep clone an object (it beats out jQuery.extend with deep flag set true by 10-20%).

jQuery.extend is pretty fast when the deep flag is set to false (shallow clone). It is a good option, because it includes some extra logic for type validation and doesn't copy over undefined properties, etc., but this will also slow you down a little.

If you know the structure of the objects you are trying to clone or can avoid deep nested arrays you can write a simple for (var i in obj) loop to clone your object while checking hasOwnProperty and it will be much much faster than jQuery.

Lastly if you are attempting to clone a known object structure in a hot loop you can get MUCH MUCH MORE PERFORMANCE by simply in-lining the clone procedure and manually constructing the object.

JavaScript trace engines suck at optimizing for..in loops and checking hasOwnProperty will slow you down as well. Manual clone when speed is an absolute must.

var clonedObject = {
  knownProp: obj.knownProp,
  ..
}

Beware using the JSON.parse(JSON.stringify(obj)) method on Date objects - JSON.stringify(new Date()) returns a string representation of the date in ISO format, which JSON.parse() doesn't convert back to a Date object. See this answer for more details.


How to get old Value with onchange() event in text box

element.defaultValue will give you the original value.

Please note that this only works on the initial value.

If you are needing this to persist the "old" value every time it changes, an expando property or similar method will meet your needs


You'll need to store the old value manually. You could store it a lot of different ways. You could use a javascript object to store values for each textbox, or you could use a hidden field (I wouldn't recommend it - too html heavy), or you could use an expando property on the textbox itself, like this:

<input type="text" onfocus="this.oldvalue = this.value;" onchange="onChangeTest(this);this.oldvalue = this.value;" />

Then your javascript function to handle the change looks like this:

    <script type="text/javascript">
    function onChangeTest(textbox) {
        alert("Value is " + textbox.value + "\n" + "Old Value is " + textbox.oldvalue);
    }
    </script>

if you are using the iCheck Jquery use the below code

 $("#CheckBoxId").on('ifChanged', function () {
                alert($(this).val());
            });