Does C have an equivalent of std::less from C++?

pointers undefined-behavior (2)

I was recently answering a question on the undefined behaviour of doing p < q in C when p and q are pointers into different objects/arrays. That got me thinking: C++ has the same (undefined) behaviour of < in this case, but also offers the standard library template std::less which is guaranteed to return the same thing as < when the pointers can be compared, and return some consistent ordering when they cannot.

Does C offer something with similar functionality which would allow safely comparing arbitrary pointers (to the same type)? I tried looking through the C11 standard and didn't find anything, but my experience in C is orders of magnitude smaller than in C++, so I could have easily missed something.

Does C offer something with similar functionality which would allow safely comparing arbitrary pointers.


First let us only consider object pointers . Function pointers bring in a whole other set of concerns.

2 pointers p1, p2 can have different encodings and point to the same address so p1 == p2 even though memcmp(&p1, &p2, sizeof p1) is not 0. Such architectures are rare.

Yet conversion of these pointer to uintptr_t does not require the same integer result leading to (uintptr_t)p1 != (uinptr_t)p2 .

(uintptr_t)p1 < (uinptr_t)p2 itself is well legal code, by may not provide the hoped for functionality.

If code truly needs to compare unrelated pointers, form a helper function less(const void *p1, const void *p2) and perform platform specific code there.


// return -1,0,1 for <,==,> 
int ptrcmp(const void *c1, const void *c1) {
  // Equivalence test works on all platforms
  if (c1 == c2) {
    return 0;
  // At this point, we know pointers are not equivalent.
  #ifdef UINTPTR_MAX
    uintptr_t u1 = (uintptr_t)c1;
    uintptr_t u2 = (uintptr_t)c2;
    // Below code "works" in that the computation is legal,
    //   but does it function as desired?
    // Likely, but strange systems lurk out in the wild. 
    // Check implementation before using
    #if tbd
      return (u1 > u2) - (u1 < u2);
      #error TBD code
    #error TBD code

No. I once tried to find a way around this but I couldn't find anything.

Your best bet is probably casting to uintptr_t and hoping the compiler does the right thing, as I ended up doing:

void *memmove(void *dest, const void *src, size_t len)
    const unsigned char *s = (const unsigned char *)src;
    unsigned char *d = (unsigned char *)dest;

    /* The most portable this is ever going to get
     * without incurring an O(n) memory penalty
    if((uintptr_t)dest < (uintptr_t)(void *)src)