# for-loop for - What is the difference between ++i and i++?

precedence --i (17)

The following C code fragment illustrates the difference between the pre and post increment and decrement operators:

int i; int j;

// Increment operators

i = 1;

j = ++i; // i is now 2, j is also 2

j = i++; // i is now 3, j is 2

In C, what is the difference between using `++i` and `i++`, and which should be used in the incrementation block of a `for` loop?

The Main Difference is

• i++ Post(After Increment) and
• ++i Pre (Before Increment)

• post if `i =1` the loop increments like `1,2,3,4,n`
• pre if `i =1` the loop increments like `2,3,4,5,n`

Please don't worry about the "efficiency" (speed, really) of which one is faster. We have compilers these days that take care of these things. Use whichever one makes sense to use, based on which more clearly shows your intent.

The difference can be understood by this simple C++ code below:

``````int i, j, k, l;
i = 1; //initialize int i with 1
j = i+1; //add 1 with i and set that as the value of j. i is still 1
k = i++; //k gets the current value of i, after that i is incremented. So here i is 2, but k is 1
l = ++i; // i is incremented first and then returned. So the value of i is 3 and so does l.
cout << i << ' ' << j << ' ' << k << ' '<< l << endl;
return 0;
``````

a=i++ means a contains current i value a=++i means a contains incremented i value

`++i` increments the value, then returns it.

`i++` returns the value, and then increments it.

It's a subtle difference.

For a for loop, use `++i`, as it's slightly faster. `i++` will create an extra copy that just gets thrown away.

I assume you understand the difference in semantics now (though honestly I wonder why people ask 'what does operator X mean' questions on rather than reading, you know, a book or web tutorial or something.

But anyway, as far as which one to use, ignore questions of performance, which are unlikely important even in C++. This is the principle you should use when deciding which to use:

Say what you mean in code.

If you don't need the value-before-increment in your statement, don't use that form of the operator. It's a minor issue, but unless you are working with a style guide that bans one version in favor of the other altogether (aka a bone-headed style guide), you should use the form that most exactly expresses what you are trying to do.

QED, use the pre-increment version:

``````for (int i = 0; i != X; ++i) ...
``````

# i++ and ++i

This little code may help to visualize the difference from a different angle than the already posted answers:

``````int i = 10, j = 10;

printf ("i is %i \n", i);
printf ("i++ is %i \n", i++);
printf ("i is %i \n\n", i);

printf ("j is %i \n", j);
printf ("++j is %i \n", ++j);
printf ("j is %i \n", j);
``````

The outcome is:

``````//Remember that the values are i = 10, and j = 10

i is 10
i++ is 10     //Assigns (print out), then increments
i is 11

j is 10
++j is 11    //Increments, then assigns (print out)
j is 11
``````

Pay attention to the before and after situations.

# for loop

As for which one of them should be used in an incrementation block of a for loop, I think that the best we can do to make a decision is use a good example:

``````int i, j;

For (i = 0; i <= 3; i++)
printf (" > iteration #%i", i);

printf ("\n");

for (j = 0; j <= 3; ++j)
printf (" > iteration #%i", j);
``````

The outcome is:

``````> iteration #0 > iteration #1 > iteration #2 > iteration #3
> iteration #0 > iteration #1 > iteration #2 > iteration #3
``````

I don't know about you, but I don't see any difference in its usage, at least in a for loop.

The reason `++i` can be slightly faster than `i++` is that `i++` can require a local copy of the value of i before it gets incremented, while `++i` never does. In some cases, some compilers will optimize it away if possible... but it's not always possible, and not all compilers do this.

I try not to rely too much on compilers optimizations, so I'd follow Ryan Fox's advice: when I can use both, I use `++i`.

Pre-crement means increment on the same line. Post-increment means increment after the line executes.

``````int j=0;
System.out.println(j); //0
System.out.println(j++); //0. post-increment. It means after this line executes j increments.

int k=0;
System.out.println(k); //0
System.out.println(++k); //1. pre increment. It means it increments first and then the line executes
``````

When it comes with OR, AND operators, it becomes more interesting.

``````int m=0;
if((m == 0 || m++ == 0) && (m++ == 1)) { //false
/* in OR condition if first line is already true then compiler doesn't check the rest. It is technique of compiler optimization */
System.out.println("post-increment "+m);
}

int n=0;
if((n == 0 || n++ == 0) && (++n == 1)) { //true
System.out.println("pre-increment "+n); //1
}
``````

In Array

``````        System.out.println("In Array");
int[] a = { 55, 11, 15, 20, 25 } ;
int ii, jj, kk = 1, mm;
ii = ++a[1]; // ii = 12. a[1] = a[1] + 1
System.out.println(a[1]); //12

jj = a[1]++; //12
System.out.println(a[1]); //a[1] = 13

mm = a[1];//13
System.out.printf ( "\n%d %d %d\n", ii, jj, mm ) ; //12, 12, 13

for (int val: a) {
System.out.print(" " +val); //55, 13, 15, 20, 25
}
``````

In C++ post/pre-increment of pointer variable

``````#include <iostream>
using namespace std;

int main() {

int x=10;
int* p = &x;

std::cout<<"address = "<<++&x<<"\n"; //error. reference can't re-assign because it is fixed (immutable)
}
``````

Shortly : ++i and i++ works same if you are not writing them in a function. If you use something like function(i++) or function(++i) you can see the difference.

function(++i) says first increment i by 1, after that put this i into the function with new value.

function(i++) says put first i into the function after that increment i by 1.

``````int i=4;
printf("%d\n",pow(++i,2));//it prints 25 and i is 5 now
i=4;
printf("%d",pow(i++,2));//it prints 16 i is 5 now
``````

The effective result of using either is identical. In other words, the loop will do the same exact thing in both instances.

In terms of efficiency, there could be a penalty involved with choosing i++ over ++i. In terms of the language spec, using the post-increment operator should create an extra copy of the value on which the operator is acting. This could be a source of extra operations.

However, you should consider two main problems with the preceding logic.

1. Modern compilers are great. All good compilers are smart enough to realize that it is seeing an integer increment in a for-loop, and it will optimize both methods to the same efficient code. If using post-increment over pre-increment actually causes your program to have a slower running time, then you are using a terrible compiler.

2. In terms of operational time-complexity, the two methods (even if a copy is actually being performed) are equivalent. The number of instructions being performed inside of the loop should dominate the number of operations in the increment operation significantly. Therefore, in any loop of significant size, the penalty of the increment method will be massively overshadowed by the execution of the loop body. In other words, you are much better off worrying about optimizing the code in the loop rather than the increment.

In my opinion, the whole issue simply boils down to a style preference. If you think pre-increment is more readable, then use it. Personally, I prefer the post-incrment, but that is probably because it was what I was taught before I knew anything about optimization.

This is a quintessential example of premature optimization, and issues like this have the potential to distract us from serious issues in design. It is still a good question to ask, however, because there is no uniformity in usage or consensus in "best practice."

You can think of internal conversion of that as a multiple statements;

``````// case 1 :

i++;

/* you can think as,
* i;
* i= i+1;
*/

// case 2

++i;

/* you can think as,
* i = i+i;
* i;
*/
``````

++i is pre-increment the other is post-increment

i++: gets the element and then increments it.
++i: increments i and then returns the element

Example:

``````int i = 0;
printf("i: %d\n", i);
printf("i++: %d\n", i++);
printf("++i: %d\n", ++i);
``````

Output:

``````i: 0
i++: 0
++i: 2
``````

• `++i` will increment the value of `i`, and then return the incremented value.

`````` i = 1;
j = ++i;
(i is 2, j is 2)
``````
• `i++` will increment the value of `i`, but return the original value that `i` held before being incremented.

`````` i = 1;
j = i++;
(i is 2, j is 1)
``````

For a `for` loop, either works. `++i` seems more common, perhaps because that is what is used in K&R.

In any case, follow the guideline "prefer `++i` over `i++`" and you won't go wrong.

There's a couple of comments regarding the efficiency of `++i` and `i++`. In any non-student-project compiler, there will be no performance difference. You can verify this by looking at the generated code, which will be identical.

The efficiency question is interesting... here's my attempt at an answer: Is there a performance difference between i++ and ++i in C?

As On Freund notes, it's different for a C++ object, since `operator++()` is a function and the compiler can't know to optimize away the creation of a temporary object to hold the intermediate value.

They both increment the number. ++i is equivalent to i = i + 1.

i++ and ++i are very similar but not exactly the same. Both increment the number, but ++i increments the number before the current expression is evaluted, whereas i++ increments the number after the expression is evaluated.

Example :

``````int i = 1;
int x = i++; //x is 1, i is 2
int y = ++i; //y is 3, i is 3
``````

``````  #include <filename>   (1)
#include "filename"   (2)
``````

`#include` includes source file, identified by filename, into the current source file at the line immediately after the directive.

The first version of the directive searches only standard include directories. The standard C++ library, as well as standard C library, is implicitly included in standard include directories. The standard include directories can be controlled by the user through compiler options.

The second version first searches the directory where the current file resides and, only if the file is not found, searches the standard include directories.

In the case the file is not found, the program is ill-formed.