localdatetime - java.time tutorial




How to convert the seconds in this format “HH:mm:ss” (4)

I want to convert the second/milliseconds in this format "HH:mm:ss" (for esamples, from 5 seconds to 00:00:05). I tried to get that format in this way:

int millis = 5000;
SimpleDateFormat df = new SimpleDateFormat("HH:mm:ss");
String time = df.format(millis);

In that way, I get "01:00:05" and not "00:00:05". Where am I wrong?


I got this to work. Let me know if it works for you. Seems like a lot of lines to do something seemingly simple..

    int millis = 5000;
    TimeZone tz = TimeZone.getTimeZone("UTC");
    SimpleDateFormat df = new SimpleDateFormat("HH:mm:ss");
    df.setTimeZone(tz);
    String time = df.format(new Date(millis));
    System.out.println(time);

I wrote a simple utility function for this task which does not require any Java version nor instantiates any unnecessary objects:

/**
 * provides a String representation of the given time
 * @return {@code millis} in hh:mm:ss format
 */
public static final String formatTime(long millis) {
    long secs = millis / 1000;
    return String.format("%02d:%02d:%02d", (secs % 86400) / 3600, (secs % 3600) / 60, secs % 60);
}

Unlike some other solutions here, this can even deal with up to 100 hours


Timezones.

The long value 5000 means 5 seconds after the epoch. For the majority of timezones, 5 seconds after the epoch is not 5 seconds past midnight local time.

Java 8 update:

java.time.LocalTime will handle the idea of a wall-clock "time of day" without you having to worry about the timezones and days implicit in java.util.Date. If you can use Java 8, and your durations will always be less than a day, then a correct version of your example can be as simple as:

int millis = 5000;
int seconds = millis / 1000; // Maybe no need to divide if the input is in seconds
LocalTime timeOfDay = LocalTime.ofSecondOfDay(seconds);
String time = timeOfDay.toString();

(I guess strictly speaking, java.time.Duration is a better model of what you want, in that it represents a certain number of seconds, rather than a time-of-day. But it's a pain to format into hh:mm:ss, so if you're always dealing with sub-24hour values, TimeOfDay gives you this formatting for free and is otherwise equivalent.)


If you're stuck with Java 7 or below, then explicitly specifying a timezone of GMT in your example code should give you the output you expect.

Here's a Scala REPL session demonstrating the problem, and Java 7 solution, on my machine:

scala> val millis = 5000
millis: Int = 5000

scala> val df = new java.text.SimpleDateFormat("HH:mm:ss")
df: java.text.SimpleDateFormat = [email protected]

scala> df.format(millis)
res0: java.lang.String = 01:00:05

scala> df.getTimeZone.getID
res1: java.lang.String = GB

scala> df.getTimeZone.getOffset(millis)
res2: Int = 3600000

scala> df.setTimeZone(java.util.TimeZone.getTimeZone("GMT"))

scala> df.format(millis)
res3: java.lang.String = 00:00:05

So you can see that my default time zone is GB, which has a 1 hour offset from GMT at the time denoted by 5000L. Setting the timezone to GMT gievs the expected output of 00:00:05.


You should get SimpleDateFormat with Locale argument.

public static String getDateFromMillis(long millis) {
    SimpleDateFormat formatter = new SimpleDateFormat("HH:mm:ss", Locale.getDefault());
    return formatter.format(new Date(millis));
}




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