machine-learning - what - when a ml model has high bias, getting more training data will help in improving the model
Neural Networks: What does “linearly separable” mean? (2)
I am currently reading the Machine Learning book by Tom Mitchell. When talking about neural networks, Mitchell states:
"Although the perceptron rule finds a successful weight vector when the training examples are linearly separable, it can fail to converge if the examples are not linearly separable. "
I am having problems understanding what he means with "linearly separable"? Wikipedia tells me that "two sets of points in a two-dimensional space are linearly separable if they can be completely separated by a single line."
But how does this apply to the training set for neural networks? How can inputs (or action units) be linearly separable or not?
I'm not the best at geometry and maths - could anybody explain it to me as though I were 5? ;) Thanks!
Look at the following two data sets:
^ ^ | X O | AA / | | A / | | / B | O X | A / BB | | / B +-----------> +----------->
The left data set is not linearly separable (without using a kernel). The right one is separable into two parts for
A' andB` by the indicated line.
I.e. You cannot draw a straight line into the left image, so that all the
X are on one side, and all the
O are on the other. That is why it is called "not linearly separable" == there exist no linear manifold separating the two classes.
Now the famous kernel trick (which will certainly be discussed in the book next) actually allows many linear methods to be used for non-linear problems by virtually adding additional dimensions to make a non-linear problem linearly separable.
Suppose you want to write an algorithm that decides, based on two parameters, size and price, if an house will sell in the same year it was put on sale or not. So you have 2 inputs, size and price, and one output, will sell or will not sell. Now, when you receive your training sets, it could happen that the output is not accumulated to make our prediction easy (Can you tell me, based on the first graph if
X will be an N or S? How about the second graph):
^ | N S N s| S X N i| N N S z| S N S N e| N S S N +-----------> price ^ | S S N s| X S N i| S N N z| S N N N e| N N N +-----------> price
S-sold, N-not sold
As you can see in the first graph, you can't really separate the two possible outputs (sold/not sold) by a straight line, no matter how you try there will always be both
N on the both sides of the line, which means that your algorithm will have a lot of
possible lines but no ultimate, correct line to split the 2 outputs (and of course to predict new ones, which is the goal from the very beginning). That's why
linearly separable (the second graph) data sets are much easier to predict.