स्क्रीनशॉट Qt/QML कैसे लें



(1)

मुझे एक समाधान मिला, बहुत आसान है, फ़ंक्शन को "कैप्चर" में बदलें

void screenCapture::capture(QString const &path) const
{
    QImage img = currentView_->grabWindow();
    img.save(path);
}

QtQuick1 उदाहरण मैं इसे QtQuick2 पर काम नहीं कर सकता

screenCapture.hpp

#include <QObject>

class QString;
class QQuickView;

class screenCapture : public QObject
{
    Q_OBJECT
public:    
    explicit screenCapture(QQuickView *parent = 0);

public slots:
    void capture(QString const &path) const;

private:
    QQuickView *currentView_;    
};

screenCapture.cpp

#include <QPixmap>
#include <QQuickView>
#include <QString>

#include "screenCapture.hpp"

screenCapture::screenCapture(QQuickView *currentView) :
    QObject(0), currentView_(currentView)
{
}

void screenCapture::capture(QString const &path) const
{
    QPixmap::grabWidget(currentView_).save(path);
}

main.cpp

#include <QGuiApplication>
#include <QQuickPaintedItem>
#include <QQuickView>
#include <QQmlContext>

#include "screenCapture.hpp"

int main(int argc, char *argv[])
{
    QGuiApplication app(argc, argv);

    qmlRegisterType<screenCapture>("Image", 1, 0, "ScreenCapture");
    qmlRegisterType<saveAbleImage>("Image", 1, 0, "SaveAbleImage");

    QQuickView view;
    view.setResizeMode(QQuickView::SizeRootObjectToView);
    view.setSource(QStringLiteral("/Users/Qt/program/experiment_apps_and_libs/funnyCamera/qml/funnyCamera/main.qml"));
    view.show();

    screenCapture screenClass(&view);
    view.rootContext()->setContextProperty("screenObject", &screenClass);

    return app.exec();
}

main.qml

import QtQuick 2.0

Rectangle{
    id : root
    width : 1024
    height : 768    

    MouseArea{
        anchors.fill: root

        onClicked: {          
            console.log("save image")
            screenObject.capture("Pictures/saveTest.jpg")
        }
    }
}

त्रुटि संदेश

QPixmap :: grabWidget को पदावनत किया गया है, QWidget :: grab () के बजाय QMetaObject :: invokeMethod: ऐसी कोई विधि QQuickView :: grab (QRect)