python - «Синоним типа устарел; в будущей версии numpy это будет пониматься как проблема(type,(1,))/'(1,) type'. ”в TensorFlow




python-3.x artificial-intelligence (2)

Я установил TensorFlow 1.10.1, но когда я попытался импортировать TensorFlow, он сказал, что мне нужна версия TensorFlow 1.10.0. Таким образом, я установил его и теперь получаю следующие предупреждения:

>>> import tensorflow
C:\Users\PC\Anaconda3\envs\tut\lib\site-packages\tensorflow\python\framework\dtypes.py:516: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  _np_qint8 = np.dtype([("qint8", np.int8, 1)])
C:\Users\PC\Anaconda3\envs\tut\lib\site-packages\tensorflow\python\framework\dtypes.py:517: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  _np_quint8 = np.dtype([("quint8", np.uint8, 1)])
C:\Users\PC\Anaconda3\envs\tut\lib\site-packages\tensorflow\python\framework\dtypes.py:518: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  _np_qint16 = np.dtype([("qint16", np.int16, 1)])
C:\Users\PC\Anaconda3\envs\tut\lib\site-packages\tensorflow\python\framework\dtypes.py:519: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  _np_quint16 = np.dtype([("quint16", np.uint16, 1)])
C:\Users\PC\Anaconda3\envs\tut\lib\site-packages\tensorflow\python\framework\dtypes.py:520: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  _np_qint32 = np.dtype([("qint32", np.int32, 1)])
C:\Users\PC\Anaconda3\envs\tut\lib\site-packages\tensorflow\python\framework\dtypes.py:525: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  np_resource = np.dtype([("resource", np.ubyte, 1)])
C:\Users\PC\Anaconda3\envs\tut\lib\site-packages\tensorboard\compat\tensorflow_stub\dtypes.py:541: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  _np_qint8 = np.dtype([("qint8", np.int8, 1)])
C:\Users\PC\Anaconda3\envs\tut\lib\site-packages\tensorboard\compat\tensorflow_stub\dtypes.py:542: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  _np_quint8 = np.dtype([("quint8", np.uint8, 1)])
C:\Users\PC\Anaconda3\envs\tut\lib\site-packages\tensorboard\compat\tensorflow_stub\dtypes.py:543: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  _np_qint16 = np.dtype([("qint16", np.int16, 1)])
C:\Users\PC\Anaconda3\envs\tut\lib\site-packages\tensorboard\compat\tensorflow_stub\dtypes.py:544: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  _np_quint16 = np.dtype([("quint16", np.uint16, 1)])
C:\Users\PC\Anaconda3\envs\tut\lib\site-packages\tensorboard\compat\tensorflow_stub\dtypes.py:545: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  _np_qint32 = np.dtype([("qint32", np.int32, 1)])
C:\Users\PC\Anaconda3\envs\tut\lib\site-packages\tensorboard\compat\tensorflow_stub\dtypes.py:550: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  np_resource = np.dtype([("resource", np.ubyte, 1)])

Если вы используете TF 2.0, быстрое решение было бы понизить ваш numy до 1.16.4. (Я использовал 1.17 и получил те же предупреждения).

1. pip uninstall numpy 
2. pip install numpy==1.16.4

Смотрите here (спасибо ymodak)


Новые заметки о выпуске NumPy (1.17):

Future Changes

Shape-1 fields in dtypes wont be collapsed to scalars in a future version
Currently, a field specified as [(name, dtype, 1)] or "1type" is interpreted 
as a scalar field (i.e., the same as [(name, dtype)] or [(name, dtype, ()]). 
This now raises a FutureWarning; in a future version, it will be interpreted 
as a shape-(1,) field, i.e. the same as [(name, dtype, (1,))] or "(1,)type" 
(consistently with [(name, dtype, n)] / "ntype" with n>1, which is already 
equivalent to [(name, dtype, (n,)] / "(n,)type").

https://docs.scipy.org/doc/numpy/release.html

Таким образом, с вашим выражением:

In [123]: np.dtype([("qint8", np.int8, 1)])                                                                  
/usr/local/bin/ipython3:1: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  #!/usr/bin/python3
Out[123]: dtype([('qint8', 'i1')])

In [124]: np.dtype([("qint8", np.int8, (1,))])                                                               
Out[124]: dtype([('qint8', 'i1', (1,))])

In [125]: np.dtype([("qint8", np.int8)])                                                                     
Out[125]: dtype([('qint8', 'i1')])

In [126]: np.dtype([("qint8", np.int8, 2)])                                                                  
Out[126]: dtype([('qint8', 'i1', (2,))])

In [127]: np.__version__                                                                                     
Out[127]: '1.17.0'