# python返回数组最大值索引 - 返回list中最大值的index

## Python:在元组列表中找到最小值,最大值 (4)

``````alist = [(1,6),(2,5),(2,4),(7,5)]

temp = map(sorted, zip(*alist))
min_x, max_x, min_y, max_y = temp[0][0], temp[0][-1], temp[1][0], temp[1][-1]``````

``temp = tuple(map(sorted, zip(*alist)))``

``````from __future__ import print_function
try:
from functools import reduce  # moved into functools in release 2.6
except ImportError:
pass

def minmaxes(seq):
pairs = tuple()
for s in map(sorted, zip(*seq)):
pairs += (s[0], s[-1])
return pairs

# functional version
def minmaxes(seq):
return reduce(tuple.__add__, ((s[0], s[-1]) for s in map(sorted, zip(*seq))))

alist = [(1,6), (2,5), (2,4), (7,5)]
min_x, max_x, min_y, max_y = minmaxes(alist)
print(' '.join(['{},{}']*2).format(*minmaxes(alist)))  # 1,7 4,6

triplets = [(1,6,6), (2,5,3), (2,4,9), (7,5,6)]
min_x, max_x, min_y, max_y, min_z, max_z = minmaxes(triplets)
print(' '.join(['{},{}']*3).format(*minmaxes(triplets)))  # 1,7 4,6 3,9``````
``alist = [(1,3),(2,5),(2,4),(7,5)]``

Fox例子：alist的输出结果是

``````min_x = 1
max_x = 7

min_y = 3
max_y = 5``````

``````alist = [(1,3),(2,5),(2,4),(7,5)]

for num, k in enumerate(['X', 'Y']):
print 'max_%s' %k, max([i[num] for i in alist])
print 'min_%s' %k, min([i[num] for i in alist])``````

``map(max, zip(*alist))``

``````>>> alist = [(1,3),(2,5),(2,4),(7,5)]
>>> zip(*alist)
[(1, 2, 2, 7), (3, 5, 4, 5)]
>>> map(max, zip(*alist))
[7, 5]
>>> map(min, zip(*alist))
[1, 3]``````

``````>>> from operator import itemgetter
>>> alist = [(1,3),(2,5),(2,4),(7,5)]
>>> min(alist)[0], max(alist)[0]
(1, 7)
>>> min(alist, key=itemgetter(1))[1], max(alist, key=itemgetter(1))[1]
(3, 5)``````